The secular trends can also be measured by the method of semi averages. The steps are:
- Divide the time series data into two equal portions. If observations are odd then either omit the middle value or include the middle value in each half.
- Take the average of each part and place these average values against the midpoints of the two parts.
- Plot the semi-averages in the graph of the original values.
- Draw the required trend line through these two potted points and extend it to cover the whole period.
- It is simple to compute the slope and
-intercept of the line drawn from two points. The trend values can be found from the semi-average trend line or by an estimated straight line as explained:
Let
For an even number of observations, the slope of the trend line can be found as:
where
The following merits and demerits of the Method of Semi Averages are as described:
Merits of Method of Semi Averages
- The method of semi-averages is simple, easy, and quick.
- It smooths out seasonal variations
- It gives a better approximation to the trend because it is based on a mathematical model.
Demerits of Method of Semi Averages
- It is a rough and objective method.
- The arithmetic mean used in Semi Average is greatly affected by very large or by very small values.
- The method of semi-averages is applicable when the trend is linear. This method is not appropriate if the trend is not linear.
Numerical Example 1: Method of Semi Averages
The following table shows the property damaged by road accidents in Punjab for the year 1973 to 1979.
Year | 1973 | 1974 | 1975 | 1976 | 1977 | 1978 | 1979 |
Property Damage | 201 | 238 | 392 | 507 | 484 | 648 | 742 |
- Obtain the semi-averages trend line
- Find out the trend values.
Solution
Let
Year | Property Damaged | Semi Total | Semi Average | Coded Year | Trend Values |
---|---|---|---|---|---|
1973 | 201 | 0 | |||
1974 | 238 | 831 | 277 | 1 | |
1975 | 392 | 2 | |||
1976 | 507 | 3 | |||
1977 | 484 | 4 | |||
1978 | 549 | 1875 | 625 | 5 | |
1979 | 742 | 6 |

The semi-average trend line
Numerical Example 2: Method of Semi Averages
The following table gives the number of books in thousands sold at a bookstore for the years 1973 to 1981
Year | 1973 | 1974 | 1975 | 1976 | 1977 | 1978 | 1979 | 1980 | 1981 |
No. of Books Sold | 42 | 38 | 35 | 25 | 32 | 24 | 20 | 19 | 17 |
- Find the equation of the semi-average trend line
- Compute the trend values
- Estimate the number of books sold for the year 1982.
Solution
Let
Year | No. of books (y) | Semi Total | Semi Average | Coded year | Trend Values |
---|---|---|---|---|---|
1973 | 42 | 0 | |||
1974 | 38 | 140 | 35 | 1 | |
1975 | 35 | 2 | |||
1976 | 25 | 3 | |||
1977 | 32 | 4 | |||
1978 | 24 | 5 | |||
1979 | 20 | 80 | 20 | 6 | |
1980 | 19 | 7 | |||
1981 | 17 | 8 |
For the year 1982, the estimated number of books sold is